Re: Oracle Analytical Functions

From: Willem Buitendyk <willem(at)pcfish(dot)ca>
To: Adam Rich <adam(dot)r(at)sbcglobal(dot)net>
Cc: pgsql-general(at)postgresql(dot)org
Subject: Re: Oracle Analytical Functions
Date: 2008-01-30 23:38:48
Message-ID: 47A10A88.4080602@pcfish.ca
Views: Raw Message | Whole Thread | Download mbox | Resend email
Thread:
Lists: pgsql-general

I tried this function but it keeps returning an error such as:

ERROR: invalid input syntax for integer: "2007-05-05 00:34:08"
SQL state: 22P02
Context: PL/pgSQL function "lagfunc" line 10 at assignment

I checked and there are no datetime values in the client_id field
anywhere in my table 'all_client_times'

I have no idea what is going on here ...

Thanks for the code though - it has taught me a lot all ready; such as
using, OUT and SETOF Record

Willem

Adam Rich wrote:
>> and I would like to create a new view that takes the first table and
>> calculates the time difference in minutes between each row so that the
>> result is something like:
>>
>> client_id,datetime, previousTime, difftime
>> 122,2007-05-01 12:01:00, 2007-05-01 12:00:00, 1
>> 455,2007-05-01 12:03:00, 2007-05-01 12:02:00, 1
>> 455,2007-05-01 12:08:00, 2007-05-01 12:03:00, 5
>> 299,2007-05-01 12:34:00, 2007-05-01 12:10:00, 24
>>
>> Any idea how I could replicate this in SQL from PG. Would this be an
>> easy thing to do in Pl/pgSQL? If so could anyone give any directions
>> as to where to start?
>>
>
> You can create a set-returning function, that cursors over the table,
> like this:
>
>
> CREATE OR REPLACE FUNCTION lagfunc(
> OUT client_id INT,
> OUT datetime timestamp,
> OUT previousTime timestamp,
> OUT difftime interval)
> RETURNS SETOF RECORD as $$
> DECLARE
> thisrow RECORD;
> last_client_id INT;
> last_datetime timestamp;
> BEGIN
>
> FOR thisrow IN SELECT * FROM all_client_times ORDER BY client_id,
> datetime LOOP
> IF thisrow.client_id = last_client_id THEN
> client_id := thisrow.datetime;
> datetime := thisrow.datetime;
> previousTime := last_datetime;
> difftime = datetime-previousTime;
> RETURN NEXT;
> END IF;
> last_client_id := thisrow.client_id;
> last_datetime := thisrow.datetime;
> END LOOP;
>
> RETURN;
> END;
> $$ LANGUAGE plpgsql;
>
> select * from lagfunc() limit 10;
> select * from lagfunc() where client_id = 455;
>
>
> Here I used an interval, but you get the idea.
>
>
>
>
>
> ---------------------------(end of broadcast)---------------------------
> TIP 6: explain analyze is your friend
>
>

In response to

Responses

Browse pgsql-general by date

  From Date Subject
Next Message Oleg Bartunov 2008-01-30 23:40:55 Re: PostgreSQL Certification
Previous Message Jeremy Harris 2008-01-30 23:30:00 Re: enabling autovacuum