extract or date_part on an interval? How many e

From: Bryce Nesbitt <bryce1(at)obviously(dot)com>
To: pgsql-sql(at)postgresql(dot)org
Subject: extract or date_part on an interval? How many e
Date: 2008-01-28 02:30:59
Message-ID: 479D3E63.2080601@obviously.com
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Hmm. Seemed so simple. But how do I get the number of years an
interval represents? extract is clearly the wrong way:

stage=# select 'now()-'1987-02-01' as interval,extract(year from
now()-'1987-02-01') as age;
interval | age
--------------------------+-----
7665 days 18:05:51.660345 | 0

select EXTRACT(year FROM INTERVAL '7665 days'); gives the same result.

select EXTRACT(day FROM now()-'1987-02-01')/365 as age; seems messy.
select (now()-'1987-02-01')/365; gives extraneous junk.

Thanks!

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