David Higgs wrote:
> On 1/13/07, Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> wrote:
> > "David" <higgsd(at)gmail(dot)com> writes:
> > > This statement works:
> > > => SELECT * FROM sal_emp WHERE 10000 = ANY (pay_by_quarter);
> > > But this does not:
> > > => SELECT * FROM sal_emp WHERE ANY (pay_by_quarter) = 10000;
> > > ERROR: syntax error at or near "ANY" at character ...
> > This is not a bug, it's the way the syntax works per SQL spec.
> > ANY must immediately follow the operator it relates to. See
> > <quantified comparison predicate> syntax in the spec.
> > regards, tom lane
> Aha, I see it in the docs now, although it's still rather unintuitive.
> Could the appropriate section on arrays be crosslinked to the ANY/ALL
> page, to preempt this question in the future?
I researched this and found this line right above the example you quoted
An alternative method is described in Section 9.17. The above query
could be replaced by:
SELECT * FROM sal_emp WHERE 10000 = ANY (pay_by_quarter);
and section 9.17 is 9.17. Row and Array Comparisons. Not sure we can do
any better than that.
Bruce Momjian bruce(at)momjian(dot)us
+ If your life is a hard drive, Christ can be your backup. +
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