Re: query with =ALL

On Mon, 14 Jun 2004, Jaime Casanova wrote:

> On Mon, 14 Jun 2004, Jaime Casanova wrote:
>
> > i have an strange result here, i'm using 7.4.2 on redhat 8
> >
> > i have a query like this
> >
> > SELECT CPA.rub_codigo, RUB.rub_descripcion, CPA.cpa_valor,
> > CPA.cpa_fechavencimiento
> > FROM rec_m_cuadropagos CPA, rec_m_rubro RUB
> > WHERE RUB.ent_codigo = CPA.ent_codigo AND RUB.rub_codigo = CPA.rub_codigo
> > AND
> > CPA.ent_codigo = 1 AND CPA.sec_codigo = 1 AND CPA.ani_codigo =
> > '2004-2005' AND
> > CPA.cic_codigo = 1 AND CPA.esp_codigo = 0 AND CPA.cur_codigo = 1
> AND
> > CPA.cur_paralelo = ALL (SELECT cur_paralelo FROM aca_t_curso WHERE
> > ent_codigo = 1 AND
> >
> > sec_codigo = 1 AND
> >
> > ani_codigo = '2004-2005' AND
> >
> > cic_codigo = 1 AND
> >
> > esp_codigo = 0 AND
> >
> > cur_codigo = 1)
> >
> > that bring no values but if i do this (the same query without the =ALL
> part)
> AFAIK, The query isn't check all values that meet the other criteria
> against all values of the subquery but instead check the value from each
> row that meets the other criteria against all the values in the subquery.
> If the values in the subquery are distinct, it's not going to return true.

> Is there another solution instead the one i'm using can you help me in that?

What precisely are you looking for as your output? Only those
combinations of the four output attributes that meet the other criteria
and that have exactly the same set as in the subselect? Hmm, I'm not sure
how to do that off hand, will think about it, but hopefully someone will
have an answer.