Re: DELETE FROM t WHERE EXISTS

On Fri, 28 Feb 2003, Stephan Szabo wrote:

>
> On Fri, 28 Feb 2003, Dan Langille wrote:
>
> > Hi folks,
> >
> > I wanted to delete "old" rows from a table. These are the rows I
> > want to keep:
> >
> > SELECT *
> > FROM clp
> > ORDER BY commit_date
> > LIMIT 100
> >
> > So I tried this:
> >
> > DELETE FROM clp
> > WHERE NOT EXISTS (
> > SELECT *
> > FROM clp
> > ORDER BY commit_date
> > LIMIT 100);
> >
> > Uhh uhh, nothing deleted. I don't understand why.
>
> As long as the inner select returns at least 1 result NOT EXISTS is
> going to return false (you haven't correlated the two queries at all).
>
> > OK, I can do this instead:
> >
> > DELETE from clp
> > where commit_log_id NOT in (
> > SELECT commit_log_id
> > FROM clp
> > ORDER BY commit_date
> > LIMIT 100);
> >
> > Can you think of a better way?
>
> Possibly something like:
> DELETE FROM clp
> WHERE NOT EXISTS (
> select * from (select * from clp order by commit_date limit 100) tmp
> where tmp.commit_log_id = clp.commit_log_id
> );
>
> But I haven't tried it for stupid errors, and am not sure that it'd end up
> being any better than NOT IN anyway.

Thank you. Here's that plan:

Seq Scan on clp (cost=0.00..544.87 rows=50 width=6) (actual
time=93.71..763.85 rows=400 loops=1)
Filter: (NOT (subplan))
SubPlan
-> Subquery Scan tmp (cost=5.37..5.62 rows=100 width=12) (actual
time=1.51..1.51 rows=0 loops=500)
Filter: (commit_log_id = $0)
-> Limit (cost=5.37..5.62 rows=100 width=12) (actual
time=0.03..1.09 rows=90 loops=500)
-> Sort (cost=5.37..5.62 rows=101 width=12) (actual
time=0.02..0.38 rows=91 loops=500)
Sort Key: commit_date
-> Seq Scan on clp (cost=0.00..2.01 rows=101
width=12) (actual time=0.23..3.88 rows=500 loops=1)
Total runtime: 768.14 msec