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Re: [SQL] Ordering a date_part() query ...

From: Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>
To: The Hermit Hacker <scrappy(at)hub(dot)org>
Cc: pgsql-sql(at)postgreSQL(dot)org
Subject: Re: [SQL] Ordering a date_part() query ...
Date: 2000-01-18 19:45:10
Message-ID: 1318.948224710@sss.pgh.pa.us (view raw or flat)
Thread:
Lists: pgsql-sql
The Hermit Hacker <scrappy(at)hub(dot)org> writes:
> SELECT ( date_part('month', stat_period) || '/' ||
>          date_part('day', stat_period)   || '/' ||
>          date_part('year', stat_period)  || ' ' ||
>          date_part('hour', stat_period)  || ':00:00' ) as "Summary - by Day/Hour",
>        sum(impressions) as impressions, sum(click_thru) as click_thru
>   FROM banner_count
> GROUP BY "Summary - by Day/Hour"
> ORDER BY "Summary - by Day/Hour"::datetime;


Uh, why don't you just GROUP BY and ORDER BY stat_period?

I also wonder whether you can't find a combination of date_trunc and
datestyle that will produce the output format you want.  Doing it
like the above sure seems like using the wrong tool for the job...

			regards, tom lane

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