Re: partitioned table and ORDER BY indexed_field DESC LIMIT 1

Pn, 2007 08 24 14:53 +0600, Anton rašė:
> Hi.
>
> I just created partitioned table, n_traf, sliced by month
> (n_traf_y2007m01, n_traf_y2007m02... and so on, see below). They are
> indexed by 'date_time' column.
> Then I populate it (last value have date 2007-08-...) and do VACUUM
> ANALYZE ON n_traf_y2007... all of it.
>
> Now I try to select latest value (ORDER BY date_time LIMIT 1), but
> Postgres produced the ugly plan:
>
> =# explain SELECT * FROM n_traf ORDER BY date_time DESC LIMIT 1;
> QUERY PL

can you test performance and send explain results of select like this :
select * from n_traf where date_time = (select max(date_time) from
n_traf);

i have similar problem with ~70M rows table (then using ordering), but
my table not partitioned.
I`m interesting how this select will works on partitioned table.

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