From: | Rikard Bosnjakovic <rikard(dot)bosnjakovic(at)gmail(dot)com> |
---|---|
To: | pgsql-novice(at)postgresql(dot)org |
Subject: | Counting booleans for two columns |
Date: | 2009-11-20 14:17:54 |
Message-ID: | d9e88eaf0911200617l76ba1ba3s83a440321f7390f5@mail.gmail.com |
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Lists: | pgsql-novice |
I have a table with values similiar to this (I have reduced the number
of rows from the actual table):
played | stats_exists
--------+--------------
t | t
t | f
t | t
t | t
f | t
t | t
t | f
What I want to do is to count the number of "t" in each column and
return the values (in two separate columns). The only thing I've
managed to do is doing a UNION, but this gives me the (correct)
results in one column only, I want the results in two (I need to
distinguish between the numbers). I did like this:
SELECT count(played) AS played
FROM matches
WHERE origin=1 AND played AND NOT training AND match_date > '2009-08-01'
UNION
SELECT count(stats_exists) AS stats
FROM matches
WHERE origin=1 AND stats_exists AND NOT training AND match_date > '2009-08-01';
with this result:
played
--------
12 <-- stats
13 <-- played
(2 rows)
How can I rewrite the SELECT so I get two values in separate columns
instead of two rows?
--
- Rikard
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