I misunderstood. :)

path '((0,0),(1,0))' is 'closed' path.

in this case, it's maybe operator calculated return length too.

----- Original Message ----- 
From: "Ioseph Kim" <pgsql-kr(at)postgresql(dot)or(dot)kr>
To: <pgsql-hackers(at)postgresql(dot)org>
Sent: Saturday, February 03, 2007 6:00 AM
Subject: Re: [HACKERS] problem of geometric operator in v8.2.1 


> when @-@ operator used at path type,
> below query maybe returns 1.
> because this path is just line.
> 
> 
> ----- Original Message ----- 
> From: "Tom Lane" <tgl(at)sss(dot)pgh(dot)pa(dot)us>
> To: "Ioseph Kim" <pgsql-kr(at)postgresql(dot)or(dot)kr>
> Cc: <pgsql-hackers(at)postgresql(dot)org>
> Sent: Saturday, February 03, 2007 5:36 AM
> Subject: Re: [HACKERS] problem of geometric operator in v8.2.1 
> 
> 
>> "Ioseph Kim" <pgsql-kr(at)postgresql(dot)or(dot)kr> writes:
>>> => select @-@ lseg '((0,0),(1,0))';
>>>  ?column?
>>> ----------
>>>         1
>>> (1 row)
>> 
>>> => select @-@ path '((0,0),(1,0))';
>>>  ?column?
>>> ----------
>>>         2
>>> (1 row)
>> 
>>> It's maybe bug in v8.2.1
>> 
>> What do you think is wrong with those answers?
>> 
>> regards, tom lane
>> 
>> ---------------------------(end of broadcast)---------------------------
>> TIP 2: Don't 'kill -9' the postmaster
>>
> 
> ---------------------------(end of broadcast)---------------------------
> TIP 5: don't forget to increase your free space map settings
>

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• Re: problem of geometric operator in v8.2.1 at 2007-02-02 21:00:29 from Ioseph Kim

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